[Problem]
Given an array of integers nums and an integer k, return the total number of subarrays whose sum equals to k.
A subarray is a contiguous non-empty sequence of elements within an array.
Example 1:
Input: nums = [1,1,1], k = 2
Output: 2
Example 2:
Input: nums = [1,2,3], k = 3
Output: 2
Constraints:
- 1 <= nums.length <= 2 * 10^4
- -1000 <= nums[i] <= 1000
- -107 <= k <= 107
[Solution]
class Solution:
def subarraySum(self, nums: List[int], k: int) -> int:
ret = 0
prefix_sum = 0
m = {0: 1}
for num in nums:
prefix_sum = prefix_sum + num
if prefix_sum - k in m:
ret += m[prefix_sum - k]
if prefix_sum not in m:
m[prefix_sum] = 1
else:
m[prefix_sum] += 1
return ret
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